![]() ![]() And then the angle is going to be the inverse tangent Of the y component, divided by the x component. ![]() And that comes out to about 6.7 km, that's the magnitude. #CAST AWAY RAFT PLUS#And so the magnitude of this, You know, we get from the Pythagorean theorem so we do 3.09 km Squared plus 5.94 km two. Displacement vector has these components. Okay, so this is like our displacement, we'll just call this D. So I actually calculated the components the 3.09 kilometers. So our total like displacement vector, you know if we go from the origin to this new location is kind of like that. So someone like this, so this is our ending point. Um and then we go 2.8 km on C 10° north of east. Um and then we go 7.2 km at um what is it southwest, 55° southwest so something like this perhaps. Um So let's see this would look kind of like this, maybe not that big vector or like that. So that would be like this And then we go 1.7 km um sort of northeast or I guess east of north. So we go there And then we go 5.1 km east. I don't have any like precise axes to measure these things with. So At 1.1 um I suppose kind of like this like I said this is the shortcoming of doing with the tablet. And then we go 1.1 kilometers at a 25 degree angle which is south of west. Um So let's see kind of like this I suppose. Yeah, so that would be down into the right sort of but at a different angle. Then from this location We go four km At 60°. So the first leg of this trip we're told is that An angle of 45° um relative or 45 degrees to the left of the y axis, And the magnitude is about 2.4 km. So I'm gonna sketch how you would do it, but then I'll just give you the numbers that I used to get the final computations. Alright, so we have a rather complicated journey undertaken by this sailor here and unfortunately I can't really do a very good graphical method on a tablet, I can't draw it. ![]()
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